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## The Reverse String Search Formula

The full syntax of the reverse string search formula is complicated and a bit confusing, so we will break down each part individually. First, though, let’s take a look at the full formula for cell **A1** in our example.

=IF(ISERROR(FIND(" ",A1) ),A1,RIGHT(A1,LEN(A1)-FIND("~",SUBSTITUTE(A1," ","~",LEN(A1)-LEN(SUBSTITUTE(A1," ","")) ) ) ) )

You can select everything above and paste it into a cell to find the last word in the string in cell **A1**.

Improvement using mid instead of right?!?

A1=The quick brown fox jumps over the lazy dog.

=IF(ISERROR(FIND(” “,A1)),A1,MID(A1,FIND(“~”,SUBSTITUTE(A1,” “,”~”,LEN(A1)-LEN(SUBSTITUTE(A1,” “,””))))+1,LEN(A1)))

Please check your fourmula – when converting it to Danish Excel i find I have to make the following change (A1);A!) etc. and not A1));A1 etc.:

=HVIS(HVIS.FEJL(FIND(” “;A1);A1);MIDT(A1;(FIND(“~”;UDSKIFT(A1;” “;”~”;LÆNGDE(UDSKIFT(A1;” “;”~”))-LÆNGDE(UDSKIFT(A1;” “;””)))))+1;LÆNGDE(A1)))

The formula uses ISERROR, not IFERROR, I’m not fluent in Danish but I think you should use ER.FEJL and not HVIS.FEJL.

Check this…

http://stackoverflow.com/questions/350264/how-can-i-perform-a-reverse-string-search-in-excel-without-using-vba

This is too nice.

=TRIM(RIGHT(SUBSTITUTE(TRIM(A1), ” “, REPT(” “, 99)), 99))

Deepak, that formula worked for me! Thank for posting it.

Beautiful!

Good tips stand the test of time, thanks!

FYI, my mid string reverse search was not quite as simple, but modified from Deepak’s version, works for most of the text strings I need. Data set coding is inconsistent, so I’m always left with some manual cleanup.

=VALUE(TRIM(RIGHT(SUBSTITUTE(TRIM(

(TRIM(LEFT(SUBSTITUTE(TRIM($A1),”XYZ”,REPT(” “,99)),99)))

), ” “, REPT(” “, 99)), 99)))

Essentially, find string “XYZ”, and THEN find the string BEFORE that (again delimited with ” “, but still could be any other delimiter or another substring).

In my case, I’m looking for product wgts buried anywhere within a product description.

“bucket o’ widgets, 21.5 oz, yellow polka dotted” (search of ” oz”, look backwards for 21.5, converted to VALUE). similar for lb, kg, or cnt, etc.

This one is the one that works for me … amazing, thank you Deepak.

Thanks a lot, Deepak. This is a great help!

Totally worked once I replaced the ” “. Thanks.

I have used this in the past and just used it again. It is a great and simple solution.

This worked for me too!! Thanks, this is awesome!!

Depak – this just worked for me too! Thanks

There is an even easier way:

=RIGHT(A1,FINDrev(” “,A1))

All you need is to define a super-simple VBA user-defined function FINDrev(), which is essentially the standard FIND() function, but working from right to left:

Public Function FINDrev(Find_text As String, Within_text As String)

FINDrev = Len(Within_text)-Len(Find_text)-InStrRev(Within_text, Find_text)+1

End Function

Thanks a lot, Andrew. This is a great help!

Nice one, Andrew!

That really is a bit of impressive latteral thinking to create a reverse find – I was looking for a vba solution to create a customer right find function, but that really is impressive…. sometimes you just get schooled… thanks Andrew

Awsome use of functions to do someting that is not inherent in excel. Used the concept to find initials for a cell with FM&L name or a F&L name.

Thank you for the excellent sample and explanation.

Was able to easily change to fit my requirements.

Thank you Andrew!!!

This seems like just what I need, except it’s not working if I have more than one character as my search value. I’m a beginner with this stuff, and any simple tips would be appreciated.

=MID(A11,FIND(“~”,SUBSTITUTE(A11,” “,”~”,LEN(A11)-LEN(SUBSTITUTE(A11,” “,””))),1)+1,999)

for extracting text from right before space

Thank you so much! Saved me so much time by using this :)! Great help.

A) Tweaking the structure of IF(ISERROR( to IFERROR and parsing as a value:

=IFERROR(VALUE(RIGHT(A1,

LEN(A1)-FIND(“~”,

SUBSTITUTE(A1,” “,”~”,

LEN(A1)-LEN(SUBSTITUTE(A1,” “,””))

)

)

)),A1)

B) Using a User Defined Function with InStrRev:

– Functions reside in Personal.XLSB,but can be viewed if not protected in VB Editor

– Functions (in Personal.XLSB) load at startup from XLStart and are global

– Path: C:\Users\[UserName]\AppData\Roaming\Microsoft\Excel\XLSTART

Public Function MyV(CellRef As String)

‘Creative Commons License – Fred Kagel

‘Reverse string search looking for normal space

Dim i As Integer

CellRef = Trim(CellRef)

i = InStrRev(CellRef, ” “) ‘finds position of space from end of string

MyV = Val(Right(CellRef, Len(CellRef) – i)) ‘Parse as value

End Function

To clarify the value of i above: inStrRev finds the first space from the end of the string (going right to left), but i returns the position of the space counting from the beginning of the string (left to right). To see the value of i, enter the MsgBox line:

Public Function MyV(CellRef As String)

Dim i As Integer

CellRef = Trim(CellRef)

i = InStrRev(CellRef, ” “) ‘finds position of space from end

Msgbox (“The value of i is: ” & i) ‘but counts left to right — thanks to Henry H

MyV = Val(Right(CellRef, Len(CellRef) – i))

End Function

Also, functions do not have to be global via Personal.xlsb; they may be self-contained within a module of a given workbook.

Excellent code, worked first time and better than I expected. Thank you so much

No need to use VBA… use this formula to get the same thing… position of first space from right of a string in cell A1…

=IF(ISERROR(FIND(” “,A1,1)),0,FIND(“\”,SUBSTITUTE(A1,” “,”\”,LEN(A1)-LEN(SUBSTITUTE(A1,” “,””))),1))

returns 0 (zero) if no spaces in the string…

To find first space to left of any position in a string, use…

=IF(ISERROR(FIND(” “,LEFT(A1,n),1)),0,FIND(“\”,SUBSTITUTE(A1,” “,”\”,LEN(LEFT(A1,n))-LEN(SUBSTITUTE(LEFT(A1,n),” “,””))),1))

where n=desired position, returns 0 (zero) if no spaces left of position n

Possible to do a reverse lookup for multiple character types? So what if I wanted to do the reverse lookup until either a “.” or a line break (CHAR(10))?

You can also use =RIGHT(A1,LEN(A1)-FIND(” “,A1)-1)

Brilliant work! Kudos to the developer of this logic

Hello,

I would like to extract some text from a cell that has this string:

Street name, Nr. 2, Bl. X5, Sc. B, Ap. 15

(sometimes string differes in format)

Street Name, Nr. 3, Bl. X2, Sc. C, Et. 3, Ap. 12

I cant use fixed length because not all cells are the same format, so i need to search for string, find next “,” (semicolon) after the found string, and than get the text between the found text and the next semicolon.

For example, find “, Bl.” and than search for “,” and extract “X5” , valuer between the found string and the next semicolon after the found string. Hope it makes sense 🙂

It should be a mix of SEARCH and LEFT/LEN/MID , im totally lost …

Can anyone help me please?

Use text to columns button with the delimiter of ,

If anyone wants the inverse of this (everything except last name), here is an extremely complicated formula to get that (note, you can do a find and replace of H3 on the formula cell to change to whatever cell you want): =LEFT(H3,LEN(H3)-LEN(IF( ISERROR(FIND(” “,H3)),H3,RIGHT(H3,LEN(H3)-FIND(“~”,SUBSTITUTE(H3,” “,”~”,LEN(H3)-LEN(SUBSTITUTE(H3,” “,””)))))))-1)

This worked would well for me – essentially using the FIND function after reversing the string.

=IFERROR(RIGHT(A1,IFERROR(FIND(“,”,TEXTJOIN(“”,1,MID(A1,SEQUENCE(LEN(A1),,LEN(A1),-1),1))),0)-2),A1)